(1+1/x)^2-(1-1/x)^2=0

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Solution for (1+1/x)^2-(1-1/x)^2=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/x+1)^2-(1-(1/x))^2 = 0

(1/x+1)^2-(1-x^-1)^2 = 0

(x^-1+1)^2-1*(1-x^-1)^2 = 0

(x^-1+1)^2-1*(1-x^-1)^2 = 0

4*x^-1 = 0

4/x = 0

4/x = 0 // * x

4 = 0

x belongs to the empty set

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